Question 760532: find three consecutive terms in AP such that their sum is 36 and the third term exceeds the first and the secnd term by two
Answer by malglu(63)   (Show Source):
You can put this solution on YOUR website! let the three terms be
x y and x+y+2
added altogether they = 36, so 2x+2y = 34
now in an AP there is a common difference between any two consecutive terms, so x+y+2 - y = y-x tidy this up and you get y=2x+2
substitute this into 2x + 2y =34 to elliminate the y term, and you get
6x = 30, so x =5
substitute this into any of the above, to get y = 12
so the three terms are
5 12 and 19
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