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What are two consecutive integers whose product is 72?
What is asked in the problem? and Given:
two consecutive numbers whose sum is 72
Representation:
Let n = the first number
n + 1 = the second consecutive number
The product of the numbers is 72
n (n+1) = 72
n^2 + n = 72
n^2 + n - 72 = 0 factor
(n + 9)(n-8) = 0
n + 9 = 0 n - 8 = 0
n = -9 n = 8
n+1 = -8 n = 9
There are two solutions:
1. the first integer is -9 and the next one is -8.
2. the first integer is 8 and the next one is 9.
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