SOLUTION: how is this done .I need to be able to understand it thanks!.Find the exact value of 1)y=sec inverse 1 2.)csc inverse (sqrt 2) 3.)csc inverse (-2) 4)y=sec inverse (-sqrt 2)

Algebra ->  Trigonometry-basics -> SOLUTION: how is this done .I need to be able to understand it thanks!.Find the exact value of 1)y=sec inverse 1 2.)csc inverse (sqrt 2) 3.)csc inverse (-2) 4)y=sec inverse (-sqrt 2)      Log On


   

Question 760404: how is this done .I need to be able to understand it thanks!.Find the exact value of
1)y=sec inverse 1
2.)csc inverse (sqrt 2)
3.)csc inverse (-2)
4)y=sec inverse (-sqrt 2)
5)y=tan inverse (-1)
6)y=arccos (-sqrt 3/2)
7.)y= sin inverse (-1)
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
1. sec+%5E-1%28+1%29=0....(result in radians)...........0°..(result in degrees)
2. csc+%5E-1+%28sqrt+2%29=pi%2F4..(result in radians).........45°..(result in degrees)
3. csc+%5E-1+%28-2%29=-pi%2F6....(result in radians)......-30°...(result in degrees)
4.sec+%5E-1%28-sqrt+2%29=%283+pi%29%2F4...(result in radians)..........135°..(result in degrees)
5. tan%5E-1%28-1%29=-pi%2F4..(result in radians)......-45°..(result in degrees)
6. arccos+%28-sqrt%28+3%2F2%29%29+=cos%5E-1%28-sqrt%283%2F2%29%29...(result in radians).....%28180-37.73i%29°..(result in degrees)
7. sin%5E-1+%28-1%29+=-pi%2F2...(result in radians)........-90°..(result in degrees)