SOLUTION: YZ has endpoints of Y (-1,-11) Z(-1,-3) what is the length

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Question 760363: YZ has endpoints of Y (-1,-11) Z(-1,-3) what is the length
Found 2 solutions by Alan3354, MathLover1:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
YZ has endpoints of Y (-1,-11) Z(-1,-3) what is the length
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The x & y axes are perpendicular to you can always make a right triangle with the points on the hypotenuse.
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d+=+sqrt%28diffy%5E2+%2B+diffx%5E2%29+=+sqrt%288%5E2+%2B+0%5E2%29

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Solved by pluggable solver: Distance Formula


The first point is (x1,y1). The second point is (x2,y2)


Since the first point is (-1, -11), we can say (x1, y1) = (-1, -11)
So x%5B1%5D+=+-1, y%5B1%5D+=+-11


Since the second point is (-1, -3), we can also say (x2, y2) = (-1, -3)
So x%5B2%5D+=+-1, y%5B2%5D+=+-3


Put this all together to get: x%5B1%5D+=+-1, y%5B1%5D+=+-11, x%5B2%5D+=+-1, and y%5B2%5D+=+-3

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Now use the distance formula to find the distance between the two points (-1, -11) and (-1, -3)



d+=+sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2+%2B+%28y%5B1%5D+-+y%5B2%5D%29%5E2%29


d+=+sqrt%28%28-1+-+%28-1%29%29%5E2+%2B+%28-11+-+%28-3%29%29%5E2%29 Plug in x%5B1%5D+=+-1, y%5B1%5D+=+-11, x%5B2%5D+=+-1, and y%5B2%5D+=+-3


d+=+sqrt%28%28-1+%2B+1%29%5E2+%2B+%28-11+%2B+3%29%5E2%29


d+=+sqrt%28%280%29%5E2+%2B+%28-8%29%5E2%29


d+=+sqrt%280+%2B+64%29


d+=+sqrt%2864%29


d+=+8

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Answer:


The distance between the two points (-1, -11) and (-1, -3) is exactly 8 units





so, the length is 8