SOLUTION: Only 1% Students solved £(ks in IAS exam. 3+5+6=151872 5+5+6=253094 5+6+7=303585 5+5+3=251573 then

Algebra ->  Customizable Word Problem Solvers  -> Numbers -> SOLUTION: Only 1% Students solved £(ks in IAS exam. 3+5+6=151872 5+5+6=253094 5+6+7=303585 5+5+3=251573 then       Log On

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Question 760218: Only 1% Students solved £(ks in IAS exam.
3+5+6=151872
5+5+6=253094
5+6+7=303585
5+5+3=251573
then

Found 3 solutions by Alan3354, pbdesai, Mubin:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Only 1% Students solved £(ks in IAS exam.
3+5+6=151872
= (3*5)(3*6)72
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a+b+c = (a*b)(a*c)??
---
5+5+6=253094
5+6+7=303585
5+5+3=251573
then
9+4+7= 3663??
==============
Repost it with that info, maybe someone will find the last 2 digits.

Answer by pbdesai(4) About Me  (Show Source):
You can put this solution on YOUR website!
Answer is- 366329.
(a×b),(a×c),{(a×b)+(a×c)-c}reverse.

Answer by Mubin(1) About Me  (Show Source):
You can put this solution on YOUR website!
9+4+7=366329
how it is solved
as(9x4=36)+(9x7=63) these gives us first 2 sets now ad both and subtract the last figure
36+63-7=92 now reverse it it will become 29
proof
5+5+3=251573
(5x5=25)+(5x3=15) these give us 2515 now to calculate for last 73
25+15=40 and now subtact last digit that is 40-3=37 and reverse it it will bcome 73