SOLUTION: [2(x-3y)+5] [3(x-3y)-2]

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Question 760205: [2(x-3y)+5] [3(x-3y)-2]
Answer by engr.gelo(2) About Me  (Show Source):
You can put this solution on YOUR website!
[2(x-3y)+5] [3(x-3y)-2] = 0
Step 1: let u = x - 3y
so the equation will be [2(u) + 5][3(u) - 2] = 0
Step 2: Expand
6(u^2) + 11(u) - 10 = 0
Step 3: substitute the value of "u" which is "x - 3y" (u = x - 3y) in the expanded equation .
6(x-3y)^2 + 11(x-3y) - 10 = 0
Step 4: Simplify
6(x^2 - 6y + 9y^2) + 11x - 33y - 10 = 0
6x^2 - 36y + 54y^2 + 11x - 33y - 10 = 0
6x^2 + 54y^2 - 69y + 11x - 10 = 0 ANSWER