SOLUTION: Please help me answer what is the Domain of the following equations and maybe some possible explanations as to how to get them/ arrive at the answer. The relations are as follows:

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Question 760021: Please help me answer what is the Domain of the following equations and maybe some possible explanations as to how to get them/ arrive at the answer. The relations are as follows:
1) y= 7-3x
2) y= the square root of 5x+3
3) x^2 + y^2 is <_ (greater than or equal to) 9
4) y= the square root of 16-x^2
5) y= 2x/1-x^2
PLEASE REPLY ASAP because i want to learn how to arrive at the answer and the answer to these relations..

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
The domain is the set of possible values for x.
In the problems you posted there are no explicit restrictions to the domain, so we look for values of x that make the calculation impossible

1) y= 7-3x can be calculated for any real number x, so its domain ia all the real numbers

2) y=sqrt%285x%2B3%29 can only be calculated when
5x%2B3%3E=0 <--> 5x%3E=-3 <--> highlight%28x%3E=-3%2F5%29
so the domain is the real numbers such that highlight%28x%3E=-3%2F5%29

3) x%5E2%2By%5E2%3E=9 (with a greater than or equal to sign) means points in the x-y plane that are at least 3 units away from the origin:
graph%28200%2C200%2C-5%2C5%2C-5%2C5%2Cx%5E2%2By%5E2%3E=9%29 That inequality determines a relation between x and y, but is a function y=f%28x%29} that would assign a single value of y to each x value. For that relation, x can take any real value.
You may have meant x%5E2%2By%5E2%3C=9 (with a lesser than or equal to sign). That means points in the x-y plane that no more than 3 units away from the origin:
graph%28200%2C200%2C-5%2C5%2C-5%2C5%2Cx%5E2%2By%5E2%3C=9%29 That restricts the values of x to highlight%28-3%3C=x%3C=3%29

4) y=sqrt%2816-x%5E2%29 cannot be calculated as a real number if 16-x%5E2%3C0, so the domain is the x values that satisfy
16-x%5E2%3E=0
Since g%28x%29=16-x%5E2 is the quadratic function with zeros at x=-4 and x=4 and a maximum in between at x=0, graphing like this
graph%28200%2C200%2C-6%2C6%2C-25%2C25%2C16-x%5E2%29, 16-x%5E2%3E=0 <--> highlight%28-4%3C=x%3C=4%29

5) y= 2x/1-x^2 = 2x%2F1-x%5E2 is not what you meant.
You meant y = 2x/(1-x^2) = 2x%2F%281-x%5E2%29.
The expression 2x%2F%281-x%5E2%29 cannot be calculated when
1-x%5E2=0 <--> system%28x=1%2Cx=-1%29or
SO the domain for y=2x%2F%281-x%5E2%29 is
all the real numbers except -1 and 1.

NOTE:
The horizontal line separating the 2x above it from the 1-x%5E2 below means that you have to calculate the expressions above and below the bar before you divide. When you cannot write 2x%2F%281-x%5E2%29 as you would on paper, you need to use parenteses to indicate the desired order of calculations.
As an analytical chemist, I have seen what happens if you do not enter the needed parentheses when using a calculator.
If I am trying to calculate f%28x%29=2x%2F%281-x%5E2%29 for x=3,
f%283%29=2%2A3%2F%281-3%5E2%29=6%2F%281-9%29=6%2F%28-8%29=-3%2F4=-0.75
The calculator would give me -0.75 if I ask for
2 X 3 ÷ ( 1 - 3 ^ 2 ) =
However, entering
2 X 3 ÷ 1 - 3 ^ 2 = will give me 2%2A3%2F1-3%5E2=6%2F1-9=6-9=-3