SOLUTION: hi so I have this question im stuck on I have to write an equation for a perpendicular slope 3,-5 2x+5y=6 so I changed it into y= 2x/5 + 6/5 then I got the reciprocal which

Algebra ->  Linear-equations -> SOLUTION: hi so I have this question im stuck on I have to write an equation for a perpendicular slope 3,-5 2x+5y=6 so I changed it into y= 2x/5 + 6/5 then I got the reciprocal which      Log On


   

Question 760005: hi so I have this question im stuck on I have to write an equation for a perpendicular slope
3,-5 2x+5y=6
so I changed it into y= 2x/5 + 6/5 then I got the reciprocal which is 5/2 then I put it into this formula y-y1=m(x-x1)
so then I got y-(-5)=5/2(x-3)
so now this is where I get stuck I cant figure out the distbutive property part after I get 5/2 im not sure how to multiply 5/2 * 3 if you could help me figure this part be a big help
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
( 3, -5 )
+2x+%2B+5y+=+6+
+5y+=+-2x+%2B+6+
+y+=+%28-2%2F5%29%2Ax+%2B+6%2F5+
The slope of a perpendicular will be +5%2F2+
+%28+y+-%28-5%29+%29+%2F+%28+x+-+3+%29+=+5%2F2+
+%28+y+%2B+5+%29+%2F+%28+x+-+3+%29+=+5%2F2+
Multiply both sides by +2%2A%28+x-3+%29+
+2%2A%28+y+%2B+5+%29+=+5%2A%28+x+-+3+%29+
+2y+%2B+10+=+5x+-+15+
+2y+=+5x+-+25+
+y+=+%285%2F2%29%2Ax+-+25%2F2+
--------------------
check:
Does it go through ( 3, -5 ) ?
+-5+=+%285%2F2%29%2A3+-+25%2F2+
+-10+=+15+-+25+
+-10+=+-10+
OK