SOLUTION: How much pure aci must be added to 2 liters of a 10% solution of acid to obtain a mixture that is 20% acid?

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: How much pure aci must be added to 2 liters of a 10% solution of acid to obtain a mixture that is 20% acid?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 759971: How much pure aci must be added to 2 liters of a 10% solution of acid to obtain a mixture that is 20% acid?
Found 2 solutions by stanbon, Janna Dominique Marasigan:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
How much pure aci must be added to 2 liters of a 10% solution of acid to obtain a mixture that is 20% acid?
-------
Equation:
acid + acid = acid
1.00x + 0.10*2 = 0.20(x+2)
------
100x + 10*2 = 20x + 20*2
-----
80x = 10*2
-----
x = 1/4 liters (amt. of pure acid to add)
=================
Cheers,
Stan H.
================

Answer by Janna Dominique Marasigan(1) About Me  (Show Source):
You can put this solution on YOUR website!
Equation:
acid + acid = acid
1.00x + 0.10*2 = 0.20(x+2)
------
100x + 10*2 = 20x + 20*2
-----
80x = 10*2
-----
x = 1/4 liters (amt. of pure acid to add)