SOLUTION: I don't want you to give me the answer, but just explain how I do can figure it out. I thought it was 7 choose 0 through 7 but then I get lost. Thank you. Suppose 40% of the res

Algebra ->  Probability-and-statistics -> SOLUTION: I don't want you to give me the answer, but just explain how I do can figure it out. I thought it was 7 choose 0 through 7 but then I get lost. Thank you. Suppose 40% of the res      Log On


   

Question 759836: I don't want you to give me the answer, but just explain how I do can figure it out. I thought it was 7 choose 0 through 7 but then I get lost. Thank you.
Suppose 40% of the restaurants in a certain part of a town are in violation of the health code. A health inspector randomly selects seven of the restaurants for inspection.
What is the probability that none of the restaurants are in violation of the health code?
What is the probability that one of the restaurants is in violation of the health code?
What is the probability that at least two of the restaurants are in violation of the health code?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
I don't want you to give me the answer, but just explain how I do can figure it out. I thought it was 7 choose 0 through 7 but then I get lost. Thank you.
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Suppose 40% of the restaurants in a certain part of a town are in violation of the health code. A health inspector randomly selects seven of the restaurants for inspection.
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Binomial Problem with n = 7 and p(in violation) = 0.4
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What is the probability that none of the restaurants are in violation of the health code?
P(x = 0) = 7C0(0.4)^0*(0.6)^7 = 1*1*0.0.0280
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The following are similar--- all binomial problems.
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Cheers,
Stan H.
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What is the probability that one of the restaurants is in violation of the health code?
What is the probability that at least two of the restaurants are in violation of the health code?
What is the probability that at least two of the restaurants are in violation of the health code?