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| Question 759812:  Mr. Edge needs 5 students, who will be arranged from tallest to shortest, for a demonstration. He has 21 students in his class. How many different combinations of students are possible for the demonstration?
 Answer by stanbon(75887)
      (Show Source): 
You can put this solution on YOUR website! Mr. Edge needs 5 students, who will be arranged from tallest to shortest, for a demonstration. He has 21 students in his class. How many different combinations of students are possible for the demonstration? -----
 Ans: 21C5 = (21*20*19*18*17)/(1*2*3*4*5) = 20,349
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 Cheers,
 Stan H.
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