SOLUTION: Solve the logarithmic equation. Be sure to reject any value that is not in the domain of the orginal logarithmic expression. {{{ln, sqrt(x+1) = 6}}}

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Solve the logarithmic equation. Be sure to reject any value that is not in the domain of the orginal logarithmic expression. {{{ln, sqrt(x+1) = 6}}}      Log On


   

Question 759718: Solve the logarithmic equation. Be sure to reject any value that is not in the domain of the orginal logarithmic expression.
ln%2C+sqrt%28x%2B1%29+=+6
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Solve the logarithmic equation. Be sure to reject any value that is not in the domain of the orginal logarithmic expression.
ln%28sqrt%28x%2B1%29%29+=+6
convert to exponential form
e^6=√x+1)
square both sides
e^12=x+1
x=e^12-1=162754.7914-1=162753.7914
check:
ln√(162754.7914)=6