SOLUTION: In a money box of 5c and 10c pieces there are 71 coins. Their total is $560. Find the number of each coin.
Im doing simultaneous equations which is where they give you 2 equatio
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Im doing simultaneous equations which is where they give you 2 equatio
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Question 759668: In a money box of 5c and 10c pieces there are 71 coins. Their total is $560. Find the number of each coin.
Im doing simultaneous equations which is where they give you 2 equations that have to be true at the same time like this:
4x + y = 9 and x - y =1
You can put this solution on YOUR website! let x be the number of 5c coins, then 71-x is the number of 10c coins, and
5x + 10*(71-x) = 560
5x + 710 - 10x = 560
-5x = -150
x = 30
this means that there are 30 5c pieces and 41 10c pieces
