SOLUTION: Find the standard form of the equation of the hyperbola with the given characteristics 1: vertices (0,+/-7) foci (0,+/-9) 2: vertices (0,+/-3) foci (0,+/-6)

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Find the standard form of the equation of the hyperbola with the given characteristics 1: vertices (0,+/-7) foci (0,+/-9) 2: vertices (0,+/-3) foci (0,+/-6)      Log On


   



Question 759620: Find the standard form of the equation of the hyperbola with the given characteristics
1: vertices (0,+/-7) foci (0,+/-9)
2: vertices (0,+/-3) foci (0,+/-6)

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Find the standard form of the equation of the hyperbola with the given characteristics
1: vertices (0,+/-7) foci (0,+/-9)
hyperbola has a vertical transverse axis
Its standard form of equation: %28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1 , (h,k)=(x,y) coordinates of center
For given hyperbola:
center: (0,0)
a=7 (distance from center to vertices)
a^2=49
c=9 (distance from center to vertices)
c^2=81
c^2=a^2+b^2
b^2=c^2-a^2=81-49=32
Equation of given hyperbola:
x%5E2%2F49-y%5E2%2F32=1
..
2: vertices (0,+/-3) foci (0,+/-6)
hyperbola has a vertical transverse axis
Its standard form of equation: %28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1 , (h,k)=(x,y) coordinates of center
For given hyperbola:
center: (0,0)
a=3 (distance from center to vertices)
a^2=9
c=6 (distance from center to vertices)
c^2=36 a^2+b^2
b^2=c^2-a^2=36-9=25
Equation of given hyperbola:
x%5E2%2F9-y%5E2%2F25=1