SOLUTION: In 1995, 70% of all children in the U.S. were living with both parents. If 25 children were selected at random in the U.S., what is the probability that at most 10 of them will be

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Question 759592: In 1995, 70% of all children in the U.S. were living with both parents. If 25 children were selected at random in the U.S., what is the probability that at most 10 of them will be living with both of their parents? Round your answer to 4 decimal places.
Answer by stanbon(75887) About Me  (Show Source):
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In 1995, 70% of all children in the U.S. were living with both parents. If 25 children were selected at random in the U.S., what is the probability that at most 10 of them will be living with both of their parents? Round your answer to 4 decimal places.
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Binomial Problem with n = 25 and P(with parents) = 0.70
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P(0<= x <=10) = binomcdf(25,0.7,10) = 0.0018
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Cheers,
Stan H.
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