SOLUTION: The perimeter of a rectangle is 212m. The length is 52m greater than 4 times the width. What's its length and width
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Question 759445: The perimeter of a rectangle is 212m. The length is 52m greater than 4 times the width. What's its length and width Answer by maheswari2188(4) (Show Source):
You can put this solution on YOUR website! Perimeter of a rectangle is 2(length+width) ie, 2(l+b)
Let the width be x,
then given l=4x+52
given P = 212
ie, 2(l+b) = 212
2(4x+52+x) = 212
5x + 52 = 212/2 = 106
5x = 106-52
x = 54/5
x = 10.8 (this is the width)
given l=4x+52
l= 4*10.8+52 = 95.2
Length is 95.2 & width is 10.8
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