SOLUTION: x^3-x^2-x+1=0
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Question 759244
:
x^3-x^2-x+1=0
Answer by
nerdybill(7384)
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x^3-x^2-x+1=0
group:
(x^3-x^2)-(x-1)=0
x^2(x-1)-(x-1)=0
(x-1)(x^2-1) = 0 (notice x^2-1 is also a "difference of squares")
(x-1)(x^2-1^2) = 0
(x-1)(x-1)(x+1) = 0
x = {-1, 1}