SOLUTION: A survey of students at a university show that 45% have a job. In a random sample of 500 students find the mean and standard deviation for the number of students who have a job.

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Question 759138: A survey of students at a university show that 45% have a job. In a random sample of 500 students find the mean and standard deviation for the number of students who have a job.

P.s. this is an intro to statistics question can u please answer it step by step
Answer by John10(297) About Me  (Show Source):
You can put this solution on YOUR website!
A survey of students at a university show that 45% have a job. In a random sample of 500 students find the mean and standard deviation for the number of students who have a job.
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Hi,
This is a binomial distribution problem.
You have n = 500, p = 0.45, q = 1- p = 1 - 0.45 = 0.55
Mean = n * p
St.deviation = SQRT(n * p * q)
You can plug the numbers in.
Hope it helps.
John