SOLUTION: Two years ago, a man was 7 times as old as his son. In 3 years time, he will be only 4 times as old as son. Find the present age of the man and of his son.
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Question 758940: Two years ago, a man was 7 times as old as his son. In 3 years time, he will be only 4 times as old as son. Find the present age of the man and of his son. Answer by Menjax(62) (Show Source):
You can put this solution on YOUR website! Defince unknowns
Let M = Man's current age
Let S = Son's current age
Dissect the question to get your equations
(M-2) = 7(S-2) #1
(M+3) = 4(S+3) #2
From #1 M = 7S-12
Sub above into #2
7S-9=4S+12
3S=21
S=7
Sub S into #1
M-2=7(7-2)
M=37
So the man's current age is 37 years old and his son's age is 7 years old
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