Question 758621: Please help I've been working on this for awhile now. thank you in advance.
Assume that a procedure yields a binomial distribution with n trials and the probability of success for one trial is p. Use the given values of n and p to find the mean μ and standard deviation σ. Also, use the range rule of thumb to find the minimum usual value μ - 2σ and the maximum usual value μ + 2σ
n=70, p=0.75
μ =
σ =
μ - 2σ =
μ + 2σ =
Answer by John10(297)   (Show Source):
You can put this solution on YOUR website! Hi,
Since you have n = 70 and p = 0.75 and q = 1 - 0.75 = 0.25
Mean = μ = np
σ = SQRT(n * p * q)
After you find the mean and standard deviation, you can plug into the two expressions.
Hope it helps you
John
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