SOLUTION: A 50% acid solution is mixed with a 25% acid solution to form a 40% acid solution. How many liters of the 25% acid solution are used to make 20 liters of the 40% acid solution?

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Question 758597: A 50% acid solution is mixed with a 25% acid solution to form a 40% acid solution. How many liters of the 25% acid solution are used to make 20 liters of the 40% acid solution?

"50x +25(20-x)=40" seems to be wrong. Help me please!

Answer by John10(297) About Me  (Show Source):
You can put this solution on YOUR website!
Hi,
You have some good idea :)
For this problem,
You need to find 2 equations for a linear system.
Let call x to be the amount of 50% acid and y to be the amount of 25% acid
We know the total is 20 L, thus the first equation is x + y = 20
Another equation would be about the mixture: 0.5x + 0.25y = 0.4(20) = 8
So you have the system of 2 linear equations:
x + y = 20
0.5x + 0.25y = 8
You can solve for x and y ( which is the amount of 25% acid)
If you need some more assistance, please email me.
Thank you!