Question 758408: how many liters of a 10 alcohol solution must be mixed with 12 liters of a 20% alcohol solution to get 14% solution Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! how many liters of a 10% alcohol solution must be mixed with 12 liters of a 20% alcohol solution to get 14% solution
------
Equation:
alch + alch = alch
0.10x + 0.20*12 = 0.14(x+12)
------
10x + 20*12 = 14x + 14*12
-----
-4x = -6*12
----
x = 18 liters (amt. of 10% solution needed)
=====================
Cheers,
Stan H.
;
(