SOLUTION: a student has 55 coins worth a total of $7.35. each coin is either a nickel or a quarter. of x is the number of nickels, then x can be determined for the equation
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Question 758336: a student has 55 coins worth a total of $7.35. each coin is either a nickel or a quarter. of x is the number of nickels, then x can be determined for the equation Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! a student has 55 coins worth a total of $7.35.
each coin is either a nickel or a quarter.
If x is the number of nickels, then x can be determined for the equation
:
Let x = no. of nickels
total coins is 55, therefore
(55-x) = no. quarters
:
.05x + .25(55-x) = 7.35
.05x + 13.75 - .25x = 7.35
.05x - .25x = 7.35 - 13.75
-.20x = -6.40
x = -6.4/-.2
x = +32 nickels
:
:
See if this checks out: 55-32 = 23 quarters
.05(32) = 1.60
.25(23) = 5.75
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total$ = 7.35
