SOLUTION: Please help me solve this equation: Four times the sum of twice the number and 7 exceeds the value of the number by 70. What is the number ?

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Please help me solve this equation: Four times the sum of twice the number and 7 exceeds the value of the number by 70. What is the number ?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 758293: Please help me solve this equation:
Four times the sum of twice the number and 7 exceeds the value of the number by 70. What is the number ?
Found 2 solutions by rfer, MathTherapy:
Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
4(2x+7) > x +70
8x+28 > x+70
7x > 70-28
7x > 42
x > 42/7
x > 6

Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!

Please help me solve this equation:
Four times the sum of twice the number and 7 exceeds the value of the number by 70. What is the number ?

Let the number be N

Then: 4(2N + 7) = N + 70

8N + 28 = N + 70

7N = 42

N, or number = 42%2F7, or highlight_green%286%29

You can do the check!!

Send comments and “thank-yous” to “D” at MathMadEzy@aol.com