SOLUTION: Hi, im stuck on this problem
:
A merchant wants to mix peanuts worth $3 per pound with jelly beans worth $1.50 per pound to make 40 pounds of a mixture worth $2.10 per pound. H
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:
A merchant wants to mix peanuts worth $3 per pound with jelly beans worth $1.50 per pound to make 40 pounds of a mixture worth $2.10 per pound. H
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Question 758219: Hi, im stuck on this problem
:
A merchant wants to mix peanuts worth $3 per pound with jelly beans worth $1.50 per pound to make 40 pounds of a mixture worth $2.10 per pound. How many pounds of each should he use?
I don't know the exact formula to use to solve it. it is beginning algebra. Found 2 solutions by Alan3354, lwsshak3:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Do it like this one.
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A nurse has a solution that is 25% alcohol and another that is 50% alcohol. How much of each must he use to make 45 liters of a solution that is 40% alcohol?
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t = amount of 25%
f = amount of 50%
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t + f = 45
25t + 50f = 45*40
You can put this solution on YOUR website! A merchant wants to mix peanuts worth $3 per pound with jelly beans worth $1.50 per pound to make 40 pounds of a mixture worth $2.10 per pound. How many pounds of each should he use?
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let x=lbs of peanuts to mix.
let y=lbs of jelly beans to mix
x+y=40
y=(40-x)
..
3x+1.50y=40*2.10
3x+1.5(40-x)=40*2.1
3x+60-1.5x=84
1.5x=24
x=16
y=40-x=24
lbs of peanuts to mix =16
lbs of jelly beans to mix=24
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