SOLUTION: A certain metal is 20% tin. How many Kg of this metal must be mixed with 80 kg of a metal that is 70% tin to get a metal that is 50% tin?
(Chart)
Kg of Metal Rate Kg of
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(Chart)
Kg of Metal Rate Kg of
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Question 758198: A certain metal is 20% tin. How many Kg of this metal must be mixed with 80 kg of a metal that is 70% tin to get a metal that is 50% tin?
(Chart)
Kg of Metal Rate Kg of tin
x .20 x
80 .70 x
x .50 x
What I have so far:
.20x+.7(80)=.5(x+?)?
You can put this solution on YOUR website! A certain metal is 20% tin. How many Kg of this metal must be mixed with 80 kg of a metal that is 70% tin to get a metal that is 50% tin?
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let x=amt of 20% tin to be mixed
80+x=amt of 50% tin final mixture
20%x+70%(80)=50%(80+x)
.2x+56=40+.5x
0.3x=16
x≈53.33
amt of 20% tin to be mixed≈53.33 Kg
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