Question 758138: my 6th grader had this for homework they barely started beg. algebra solving for x. Don't know how to help him with the problem below. Please help
the math team decided to sell customized pocket protectors as a fundraiser. These were truly a hot item in our school, and $240 was raised. Cecily had originally suggested a price that was $2 lower for each item, but if the team had agreed to that price they would have had to sell 20 more pocket protectors to get the $240
How many pocket protectors did they actually sell? what was the price of each.
Answer by htmentor(1343)   (Show Source):
You can put this solution on YOUR website! Let p = the original price
Let n = the number sold
Since the amount raised is $240, we have n*p = 240
If they had lowered the price by $2, they would have needed to sell 20 more to make $240.
The equation for this is (n+20)(p-2) = 240
Solve for p in the 1st equation and substitute in the 2nd:
(n+20)(240/n-2) = 240
If you perform the multiplication and simplify, your are left with
n^2 + 20n - 2400 = 0
Factor:
(n+60)(n-40) = 0
Take the positive solution, n = 40
So they sold 40 pocket protectors at a cost of $6 each
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