SOLUTION: please see if this problem is correct and thanks in advance Factor completely: 3x^2+12x+12 3x^2+(2^2 3)x+2^2.3 3[(x+2)^2] 3(x+2^2) Thanks a millon

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Question 75793: please see if this problem is correct and thanks in advance

Factor completely: 3x^2+12x+12
3x^2+(2^2 3)x+2^2.3
3[(x+2)^2]
3(x+2^2)
Thanks a millon
Answer by bucky(2189) (Show Source):
You can put this solution on YOUR website!
Factor completely:
.
3x^2+12x+12
.
3x^2+(2^2*3)x+2^2*3 <--- this is correct. But you might have found it easier
to just look at the coefficients of the terms in the original polynomial and
recognize that they were all divisible by 3. Then you could have factored out
the 3 to get 3(x^2 + 4x + 4)
.
3[(x+2)^2] <--- this is correct
.
3(x+2^2) <--- this is not correct. 2^2 is 4 and therefore what you have in
the parentheses is x + 4. I'm pretty sure that all that you meant to do
was to delete the brackets leaving just the answer as:
.
3(x + 2)^2 <--- and this is correct
.
With the exception of this minor error, you went about the problem correctly. You seem
to have the process down correctly. Good work!