SOLUTION: find three consecutive odd integers such that 10 times the first when added to the third is equal to the square of the second

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Question 757773: find three consecutive odd integers such that 10 times the first when added to the third is equal to the square of the second
Answer by sachi(548) About Me  (Show Source):
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let the 3 consecutive odd integers are x-2,x,x+2
10 times the first when added to the third is equal to the square of the second
so 10(x-2)+(x+2)=x^2
or 10x-20+x+2=x^2
or x^2-11x+18=0 by simplifying
or x^2 -2x-9x+18=0
or x(x-2)-9(x-2)=o
or (x-2)(x-9)=0
or x=2 or 9 =9 rejecting the even no 2
so the 3 consecutive odd integers are either 7,9,11