SOLUTION: The length of a rectangle is 2 inches longer than the width. If the area is 315 square inches, find the rectangle's dimensions. Round your answers to the nearest tenth of an inch.

Algebra ->  Rectangles -> SOLUTION: The length of a rectangle is 2 inches longer than the width. If the area is 315 square inches, find the rectangle's dimensions. Round your answers to the nearest tenth of an inch.       Log On


   

Question 757732: The length of a rectangle is 2 inches longer than the width. If the area is 315 square inches, find the rectangle's dimensions. Round your answers to the nearest tenth of an inch.
Answer by John10(297) About Me  (Show Source):
You can put this solution on YOUR website!
The length of a rectangle is 2 inches longer than the width. If the area is 315 square inches, find the rectangle's dimensions. Round your answers to the nearest tenth of an inch.
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Let x be the length then the width is (x - 2).
The area is A = Length * Width = x(x - 2) = 315
x^2 - 2x - 315 = 0
Solve for x (length). From there, you can find the width.
Hope it helps! John