SOLUTION: PLEASE HELP ME SOLVE One has 40% solution the other has 25%. How many liters of each solution must be mixed to obtain 100 liters of 36% solution. I have been working on this prob

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Question 757722: PLEASE HELP ME SOLVE
One has 40% solution the other has 25%. How many liters of each solution must be mixed to obtain 100 liters of 36% solution. I have been working on this problem for 2 hours and I still cant get the right answer
Answer by John10(297) About Me  (Show Source):
You can put this solution on YOUR website!
Hi,
For this kind of problem, you must create a linear system of 2 equations to solve for each type.
Let x be amount of 40% solution
----y--------------25% solution
The first equation you will have is the total of 2 solutions. You know that the total is 100 L: x + y = 100
The second equation is the mixture between them to create a new solution:
0.4x + 0.25y = (0.36)(100) = 36

So you will have a system:
x + y = 100
0.4x + 0.25y = 36
Solve the system then you will have the amount of each solution.
Good luck! John