SOLUTION: Solve: -8log2-8n = 0 (this is log, base 2)

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Question 757713: Solve: -8log2-8n = 0
(this is log, base 2)
Found 2 solutions by stanbon, tommyt3rd:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
-8log2(-8n)= 0
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Divide both sides by -8 to get:
log2(-8n) = 0
----
Equation:
-8n = 2^0 = 1
----
n = -1/8
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Cheers,
Stan H.
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Answer by tommyt3rd(5050) About Me  (Show Source):
You can put this solution on YOUR website!
Assuming you are writing:

%0D%0A-8%2Alog2%28-8n%29+=+0%0D%0A

Then
%28-8log2%28-8n%29%29%2F%28-8%29=0%2F%28-8%29=0%0D%0A


2%5E%28log2%28-8n%29%29=2%5E0%0D%0A


-8n=1

n=-1/8