SOLUTION: . Dave has 8 more dimes than nickels in his pocket. In total, the coins in his pocket are worth $3.05. How many of each type of coin does he have?

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Question 757704: . Dave has 8 more dimes than nickels in his pocket. In total, the coins in his pocket are worth
$3.05. How many of each type of coin does he have?

Found 2 solutions by stanbon, josmiceli:
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
Dave has 8 more dimes than nickels in his pocket. In total, the coins in his pocket are worth $3.05. How many of each type of coin does he have?
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Quantity Eq: d = n + 8
Value: 10d + 5n = 305 cents
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Substitute for "d" and solve for "n":
10(n+8)+5n = 305
15n + 80 = 305
15n = 225
n = 15 (# of nickels)
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Solve for 'd:
d = n+8
d = 23 (# of dimes)
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Cheers,
Stan H.
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Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website!
Let = number of nickels he has
Let = number of dimes he has
given:
(1)
(2) ( in cents )
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(1)
Multiply both sides by
and add (1) and (2)
(1)
(2)

and, since
(1)
(1)
(1)
(1)
He has 15 nickels and 23 dimes
check:
(2)
(2)
(2)
OK