SOLUTION: Several different bus routes stop at the Spooner Street Station. One bus makes this stop every 24 minutes and another bus makes this stop every 16 minutes. If both buses arrive

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Question 757570:
Several different bus routes stop at the Spooner Street Station. One bus makes this stop every 24 minutes and another bus makes this stop every 16 minutes. If both buses arrive at the stop at 3:10 PM, when will they again arrive at the same time
Found 2 solutions by josmiceli, MathLover1:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The number of minutes past 3:10 PM must be
evenly divided by both 24 and 16.
First, I tried +16%2A24+=+384+
Then I took half of that
+384%2F2+=+192+
+192%2F24+=+8+
+192%2F16+=+12+
----------------
Then I tried half of that
+192%2F2+=+96+
+96%2F24+=+4+
+96%2F16+=+6+
--------------
This says that the bus that stops every 24 min will
make 4 stops, and the bus that stops every 16 min
will make 6 stops in 96 min
-----------------------
+96+=+60+%2B+36+
3:10 + 1 hr + 36 min = 4:46
At 4:46 PM, they arrive at the same time


Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!


The number of minutes past 3%3A10 PM must be
evenly divided by both 24 and 16.
First, I tried +16%2A24+=+384+
Then I took half of that
+384%2F2+=+192+
+192%2F24+=+8+
+192%2F16+=+12+

Then I tried half of that
+192%2F2+=+96+
+96%2F24+=+4+
+96%2F16+=+6+

This says that the bus that stops every 24 min will
make 4 stops, and the bus that stops every 16 min
will make 6 stops in 96 min

+96+=+60+%2B+36+
3%3A10+%2B+1+hr+%2B+36+min+=+4%3A46
At 4%3A46 PM, they arrive at the same+time