SOLUTION: Given two rectangles, one with length = l and width = w, and the second rectangle with length = 2l and width = 4w. How much larger will the perimeter of the second rectangle be tha

Algebra ->  Rectangles -> SOLUTION: Given two rectangles, one with length = l and width = w, and the second rectangle with length = 2l and width = 4w. How much larger will the perimeter of the second rectangle be tha      Log On


   

Question 757454: Given two rectangles, one with length = l and width = w, and the second rectangle with length = 2l and width = 4w. How much larger will the perimeter of the second rectangle be than the perimeter of the first rectangle?
A. P2 - P1 = 2 * (l + 3w)
B. P2 = 2P1 + w
C. P2 = 2P1 + 4w
D. P2 = P1 + w
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

one of two rectangles with length l and width w has perimeter
P%5B1%5D=2l%2B2w
P%5B1%5D=2%28l%2Bw%29
and the second rectangle with length 2l and width 4w has perimeter P%5B2%5D=2%2A2l%2B2%2A4w
P%5B2%5D=4l%2B8w

P%5B2%5D-P%5B1%5D=4l%2B8w-%282l%2B2w%29
P%5B2%5D-P%5B1%5D=4l%2B8w-2l-2w%29
P%5B2%5D-P%5B1%5D=2l%2B6w
P%5B2%5D-P%5B1%5D=2%28l%2B3w%29
so, answer is A