SOLUTION: In △JKL, solve for x.
Triangle JKL where angle K is a right angle. KL measures 34; JL measures x; angle J measures 27 degrees.
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-> SOLUTION: In △JKL, solve for x.
Triangle JKL where angle K is a right angle. KL measures 34; JL measures x; angle J measures 27 degrees.
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Question 757408: In △JKL, solve for x.
Triangle JKL where angle K is a right angle. KL measures 34; JL measures x; angle J measures 27 degrees. Answer by Cromlix(4381) (Show Source):
You can put this solution on YOUR website! Trigonometric ratio.
Sin = Opposite/ Hypotenuse
sin 27 = 34/x
Cross multiply
x = 34/sin 27
x = 74.9
Hope this helps
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