SOLUTION: Can you explain how to solve logarithmic expressions so that they are single logarithms? Example: How would you solve: log 15+ log 8 as a single expression.

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Question 757382: Can you explain how to solve logarithmic expressions so that they are single logarithms?
Example:
How would you solve:
log 15+ log 8 as a single expression.

Found 3 solutions by MathLover1, stanbon, josmiceli:
Answer by MathLover1(20850) About Me  (Show Source):
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
log 15+ log 8 as a single expression.
--------
Log Laws:
log(A) + log(B) = log[A*B]
log(A) - log(B) = log[A/B]
log[A^n] = n*log[A]
logA{B] = log(B)/log(A)
----
These are the laws you must learn.
======================================
Your problem:
log(15) + log(8) = log(15*8) = log(120)
=========================================
Cheers,
Stan H.
=================

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The rule is:
+log%28a%29+%2B+log%28b%29+=+log%28%28+a%2Ab+%29%29+
---------------------------
You can see this very well if you use
logs to the base +10+
-------------
Suppose the equation is:
+log%28+10000+%29+%2B+log%28+100000000+%29+
which is
+log%28+10%5E4+%29+%2B+log%28+10%5E8+%29+
+4+%2B+8+=+12+
---------------
Applying the rule:
+log%28+10%5E4+%29+%2B+log%28+10%5E8+%29+=+log%28%28+10%5E4+%2A+10%5E8+%29%29+
+log%28+10%5E4+%2A+10%5E8+%29+=+log%28+10%5E12+%29+
and
+log%28+10%5E12+=+12+%29+
so, the rule works.
In words, the rule says, " Add the logs of 2 numbers
and you will get the
same result if you multiply the 2 numbers
themselves and then take the log of that product.
Hope this helps