SOLUTION: Ron and pat leaves for the beach at the same point. Ron leaves first pat leaves 45 mins later traveling 10 mph faster then Ron. pat passes ron 4 hours later. find the rate of each
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Question 757322: Ron and pat leaves for the beach at the same point. Ron leaves first pat leaves 45 mins later traveling 10 mph faster then Ron. pat passes ron 4 hours later. find the rate of each driver. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Ron and pat leaves for the beach at the same point.
Ron leaves first, Pat leaves 45 mins later traveling 10 mph faster
than Ron.
Pat passes Ron 4 hours later. find the rate of each driver.
:
Since we a dealing in hrs here, convert 45 min to .75 hrs
:
From the information given, we know
P's travel time = 4 hrs
R's travel time = 4.75 hrs
:
let s = R's rate
then
(s+10) = P's rate
:
When P catches R, they will have traveled the same distance.
Write a distance equation; Dist = time * speed
:
R's dist = P's dist
4.75s = 4(s+10)
4.75s = 4s + 40
4.75s - 4s = 40
.75s = 40
s = 40/.75
s = 53 mph is R's rate
then
53 + 10 = 63 mph is P's rate
:
:
You can check this out for yourself, determine the distance each
traveled, should be the same. (dist = rate * time)
