Question 757293: Amount of fencing in linear feet needed for the perimeter of a rectangular lot with diagonal length 38 meters and a side length 32 meters? Answer by Cromlix(4381) (Show Source):
You can put this solution on YOUR website! if the diagonal measured 38 metres and the side length
measured 32 metres, using Pytagoras the base side measures 20.5 metres
Base length^2 + side length^2= diagonal length^2
Diagonal length^2 - side length^2 = base length^2
Square root of base length square = 20.5 metres.
Perimeter = 2 x base length + 2 x side length.
= 2 x 32 + 2 x 20.5
= 64 + 41
= 105 metres = 344.49 feet
Hope this helps.
:-)
