SOLUTION: The width of a rectangle is 18 cm less than the length. The perimeter is 88 cm. Find the dimensions of the rectangle.
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Question 757213: The width of a rectangle is 18 cm less than the length. The perimeter is 88 cm. Find the dimensions of the rectangle. Answer by LearnWithMajor(33) (Show Source):
You can put this solution on YOUR website! The perimeter of a rectangle is 2 times the sum of length and width.
P = 2(l+w) The problem tells us the perimeter is 88
88 = 2(l+w) It also says the width is 18 cm less than the length.
w = l - 18
Substituting l-18 for w and then solving for l.
88 = 2(l+l-18)
88 = 2(2l-18)
44 = 2l-18
62 = 2l
31 = l
w = l-18 = 31-18=13
Dimensions of rectangle is 13 cm by 31 cm
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