SOLUTION: identify the center and the radius of {{{(x-2)^2 + (y-1)^2=9}}}

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Question 757164: identify the center and the radius of %28x-2%29%5E2+%2B+%28y-1%29%5E2=9

Found 2 solutions by sachi, LearnWithMajor:
Answer by sachi(548) About Me  (Show Source):
You can put this solution on YOUR website!
(x-2)2 + (y-1)2=9
comparing with standard eqn of circle
(x-a)^2 + (y-b)^2=r^2
r^=9=3^2
or radius =r =3
& the centre is (a,b)=(2,1)

Answer by LearnWithMajor(33) About Me  (Show Source):
You can put this solution on YOUR website!
This equation has the standard form of a circle %28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2 where (h,k) is the center of the circle and r is the radius of the circle.
Therefore for our above equation h = 2, k = 1, and r^2 = 9. Taking the positive squareroot of 9 we get that r = 3. +sqrt%289%29+=+3+
The center of the circle is at (2,1) and the radius of the circle is 3.