SOLUTION: Match each graph with the correct equation on the right. This graph is a curve graph that starts at points(-1,20) the curve drops down to points (3, -4) and back up to points (6,2

Algebra ->  Graphs -> SOLUTION: Match each graph with the correct equation on the right. This graph is a curve graph that starts at points(-1,20) the curve drops down to points (3, -4) and back up to points (6,2      Log On


   

Question 75693This question is from textbook Beginning Algebra
: Match each graph with the correct equation on the right.
This graph is a curve graph that starts at points(-1,20) the curve drops down to points (3, -4) and back up to points (6,20). I am not sure if these are right I just duplicated the graph to get the coordanance. The equations are:
a)y=-x^2+1
b)y=2x
c)y=x^2-4x
d)y=-x=1
e)y=-x^2+3x
f)y=x^2+1
g)y=x+1
h)y=2x^2
Thanks for your help.
 This question is from textbook Beginning Algebra

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Since the graph is opening upward, we know the leading coefficient is positive and we know its a quadratic since its a parabola. So lets try y=2x%5E2
20=2%28-1%29%5E2 Plug in (-1,20
20=2 not true. So thats not the equation
Lets try
y=x%5E2-4x Plug in (-1,20)
20=%28-1%29%5E2-4%28-1%29
20=1%2B4
20=5 not true. So thats not the equation
y=x%5E2%2B1 Plug in (-1,20)
20=%28-1%29%5E2%2B1
20=1%2B1
20=2 not true. So thats not the equation
It seems that none of these equations work. Double check your graph to see if you copied the coordinates down right.