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Question 756884: Solve the equation in the real number system.
X^4-3x^3+12x^2-48x-64=0
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Solve the equation in the real number system.
X^4-3x^3+12x^2-48x-64=0
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use rational roots theorem:
...0..|....1.....-3......12....-48.....-64
...1..|....1.....-2......10....-38....-102
...2..|....1.... -1......10....-38....-140
...3..|....1.......0......12....-12...-100
...4..|....1......1.......16.....16.......0 (4 is a root)
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...0...|....1......1.......16.....16
..-1..|....1.....0........16......0 (-1 is a root)
f(x)=(x-4)(x+1)(x^2+16x)
roots are:-1, 4,and 2 non-real roots
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