SOLUTION: Suppose at time t=0, the number of bacteria present is 2500. If t minutes later the number of bacteria is given by N(t)=2500(2.4)^(t/12) Then, to the nearest integer, the numbe

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Suppose at time t=0, the number of bacteria present is 2500. If t minutes later the number of bacteria is given by N(t)=2500(2.4)^(t/12) Then, to the nearest integer, the numbe      Log On


   

Question 756438: Suppose at time t=0, the number of bacteria present is 2500. If t minutes later the number of bacteria is given by N(t)=2500(2.4)^(t/12)
Then, to the nearest integer, the number of bacteria present after an hour will be
299,000
196,550
197,366
229,443
199,066
Please explain this to me, thank you.
Answer by Cromlix(4381) About Me  (Show Source):
You can put this solution on YOUR website!
Your formula: N(t) = 2500* (2.4)^(t/12)
In an hour (60 mins) the formula will become:-
N(t) = 2500* (2.4)^(60/12)
N(t) = 2500* (2.4)^(5)
N(t) = 199066 bacteria
Hope this helps.
:-)