SOLUTION: Please explain this to me, i don't understand this. For any base b, log_b ∛(b^5 ) is log_b 3b log_b (3b/5) 5/3 3/5 5b/3

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Please explain this to me, i don't understand this. For any base b, log_b ∛(b^5 ) is log_b 3b log_b (3b/5) 5/3 3/5 5b/3       Log On


   

Question 756431: Please explain this to me, i don't understand this.


For any base b, log_b ∛(b^5 )
is
log_b 3b
log_b (3b/5)
5/3
3/5
5b/3
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
For any base b, log_b ∛(b^5 )
log_b ∛(b^5 )
log%28b%2Croot%283%2Cb%5E5%29%29
log%28b%2C%28b%5E%285%2F3%29%29%29=5%2F3
Rule:log of base(b) raised to an exponent(5/3)=exponent(5/3)
Example:log of base(10) raised to expoment(2)=2
log(10^2)=log100=2