Question 756419: I need help solving this. Graph the function. g(x)=2/3log(base2)(x-4)+1. Plot 2 points and the asymptotes if any.
Thanks for viewing Answer by josgarithmetic(39617) (Show Source):
The (2/3) factor squashes the graph vertically by that factor.
The +1 moves the graph upward by 1 unit.
Note: The site system is not rendering properly. The graph should decrease rapidly as it goes toward the left; NOT be cut-off. There IS an vertical asymptote on the left of the graph. x=4 is this vertical asymtptote.