SOLUTION: Given tan0 -sqrt3/1 and lies in Quadrant IV, find sec0
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Question 756277
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Given tan0 -sqrt3/1 and lies in Quadrant IV, find sec0
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Given tan0 -sqrt3/1 and lies in Quadrant IV, find sec0
tanx=-√3/1=–√3
secx=√(tan^2x+1)=√(3+1)=√4=2