SOLUTION: Determine all of the solutions in the interval 0° ≤ θ < 360°. (Enter your answers as a comma-separated list. Round your answers to one decimal place.)
23 sin2 θ &#
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-> SOLUTION: Determine all of the solutions in the interval 0° ≤ θ < 360°. (Enter your answers as a comma-separated list. Round your answers to one decimal place.)
23 sin2 θ &#
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Question 756247: Determine all of the solutions in the interval 0° ≤ θ < 360°. (Enter your answers as a comma-separated list. Round your answers to one decimal place.)
23 sin2 θ − cos 2θ = 0 Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Determine all of the solutions in the interval 0° ≤ θ < 360°. (Enter your answers as a comma-separated list. Round your answers to one decimal place.)
23 sin^2θ − cos 2θ = 0
23 sin^2θ − cos^2θ+sin^2θ = 0
24sin^2θ-cos^2θ=0
24sin^2θ-1+sin^2θ=0
25sin^2θ=1
sin^2θ=1/25
sinθ=±1/5
θ=11.5º, 168.5 (in Q1 and Q2 where sin>0)
and
θ=191.5º, 348.5 (in Q3 and Q4 where sin<0)
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