SOLUTION: The length of a rectangle is 3 feet less than twice the width of the rectangle. If the perimeter of the rectangle is 354 feet, find the width and the length
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-> SOLUTION: The length of a rectangle is 3 feet less than twice the width of the rectangle. If the perimeter of the rectangle is 354 feet, find the width and the length
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Question 756186: The length of a rectangle is 3 feet less than twice the width of the rectangle. If the perimeter of the rectangle is 354 feet, find the width and the length Answer by Cromlix(4381) (Show Source):
You can put this solution on YOUR website! width = x
length = (2x - 3)
Perimeter = 2 * width + 2 * length
=> 2x + 2(2x - 3) = 354ft
=> 2x + 4x - 6 = 354
=> 6x = 354 + 6
=> 6x = 360
=> x = 60ft
Width = 60ft
Length = 117ft
Proof:
Perimeter = 2*60 + 2*117 = 354ft.
Hope this helps
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