SOLUTION: 2 planes leave Newyork AT 10am, one heading for Europe at 600mph and one heading in the opposite direction at 150mph. At what time will they be 900 miles apart?

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Question 75591: 2 planes leave Newyork AT 10am, one heading for Europe at 600mph and one heading in the opposite direction at 150mph. At what time will they be 900 miles apart?
Answer by psbhowmick(878) About Me  (Show Source):
You can put this solution on YOUR website!
Let the planes be 900 miles apart after 't' hours from start.

SPEED+=+DISTANCE%2FTIME or DISTANCE+=+SPEEDxTIME

In 't' hrs. the first plane travels = 600%2At miles.
In 't' hrs. the second plane travels = 150%2At miles.
After 't' hours the distance between the two planes flying in opposite directions = (600t + 150t) = 750t mph.
When, this distance is 900 miles,
750t+=+900
t+=+900%2F750+=+6%2F5
So the reqd. time vis t = 1.2 hrs. = 1.2*60 min = 72 min = 1 hr 12 min.
Thus the planes will be 900 miles apart at 11:12 am.